What is the integral of 1/(x√(x^2-4)) dx?
So I know that I am going to have to factor out the 4 and use the arcsec trig identity but I've having trouble getting to a viable u-substitution.
I've gotten to factoring like this so far:
√(x^2-4) = √[2^2(x^2/2^2 - 1)] = 2√((x/2)^2 - 1))
I could do
u = x/2
du = 1/2 dx
But that still leaves the x in front of the radical.
How can I solve this?