A 4.86 kg sample of a solution of the solute chloroform in the solvent (C2H5)2O that has a concentration of 1.91 pph by mass chloroform is available. Calculate the amount (g) of CHCl3 that is present in the sample.
Molar Mass (g/mol)
CHCl3 119.38
(C2H5)2O 74.12
Density (g/mL):
CHCl3 1.483
(C2H5)2O 0.7138
Name/Formula:
chloroform
CHCl3
diethyl ether
(C2H5)2O
pph = parts per hundred = %.
1.91 pph = 1.91%
4.86 kg = 4860 g sample; of which there is 1.91% CHCl3. Therefore, the amount of CHCl3 is
4,860 g x 0.0191 = ??
Check my thinking. Check my work.
5. The tetraethyl lead [Pb(C2H5)4] in a 25.00-mL sample of aviation gasoline was shaken with 15.00mL of 0.02095M I2
To calculate the amount of CHCl3 present in the sample, we need to use the concentration given in parts per hundred (pph) by mass.
First, let's convert the concentration from pph to a decimal fraction:
1.91 pph = 1.91/100 = 0.0191
Next, we calculate the mass of CHCl3 in the sample:
Mass of CHCl3 = Mass of sample * concentration of CHCl3
Given:
Mass of sample = 4.86 kg
Concentration of CHCl3 = 0.0191
Mass of CHCl3 = 4.86 kg * 0.0191 = 0.092826 kg
To convert the mass of CHCl3 from kg to grams, multiply by 1000:
Mass of CHCl3 = 0.092826 kg * 1000 = 92.826 g
Therefore, there are 92.826 grams of CHCl3 present in the sample.