PreCalculus
posted by Lucy .
Find a numerical value of one trigonometric function of x if
tanx/cotx  secx/cosx = 2/cscx
a) cscx=1
b) sinx=1/2
c)cscx=1
d)sinx=1/2

(sinx/cosx)/(cosx/sinx)  (1/cosx)/cosx = 2sinx
(sin^2 x)/(cos^2 x)  1/cos^2 x = 2sinx
(sin^2 x  1)/cos^2 x = 2sinx
(sin^2 x  1)/(1  sin^2 x) = 2sinx
1 = 2sinx
sinx = 1/2