posted by Lucy .
State the period and phase shift of the function y=-4tan(1/2x + 3pi/8)
a) 2pi, -3pi/4
b) pi, 3pi/8
c) 2pi, 3pi/8
d) pi, -3pi/8
2) What is the equation for the inverse of y=cos x+3:
b) y=Arccos x-3
c) y=Arccos x+3
Thanks for your help
in y=-4tan(1/2x + 3pi/8)
y = -4 tan (1/2)[x + 3pi/4]
so the period is 2pi/(1/2) = 4pi which is none of your choices.
Did you type your questions or answers correctly??
the phase shift would be 3pi/4 radians to the left.
the inverse of y = cos x+3 is x = cos y+3
then cos y = x-3
and y = arccos(x-3)
I double checked my typing on the first problem and everything was entered correctly.
then the book is wrong
I am not surprised as I have found many errors thus far.
Thanks for helping