how do i solve this...i have no clue
(x+2)(x-3)= (x-3)(x-3)
It has no solution except x=3
how did you get x=3
Divide both sides by x-3.
x+2=x-3
From there, I don't know how bobpursley got x=3 either.
Did you post the equation correctly?
Sorry that I can't be of more help. Thanks for asking.
To solve the given equation (x+2)(x-3) = (x-3)(x-3), you can follow these steps:
Step 1: Expand both sides of the equation by applying the distributive property.
(x+2)(x-3) = (x-3)(x-3)
(x^2 - 3x + 2x - 6) = (x^2 - 3x - 3x + 9)
Step 2: Simplify the equation by combining like terms on both sides.
(x^2 - x - 6) = (x^2 - 6x + 9)
Step 3: By comparing the coefficients of the variables on each side of the equation, you can determine if they are equal.
Coefficients of x^2: 1 = 1 (equal)
Coefficients of x: -1 = -6 (not equal)
Constant terms: -6 = 9 (not equal)
Since the coefficients of x and the constant terms are not equal on both sides of the equation, it implies that there is no value of x that can satisfy the equation. Therefore, the given equation has no solution.