Calculus

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Solve for x using logs.
4 * 16^x = 10 * 11^x


Do you start by multiply 4 times 16 then 10 times 11, and then what? Or am I completely wrong?

  • Calculus -

    you could do
    4^1 * (4^2)^x = 10*11^x
    4^(2x+1) = 10*11^x
    now take the log of both sides
    log(4^(2x+1)) = log10 + log11^x
    (2x+1)log4 = 1 + xlog11
    (2log4)x + log4 = 1 +xlog11
    x(2log4 - log11) = 1-log4
    x = (1-log4)/(2log4-log11)
    x = 2.44544

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