How are the sides of a right triangle founded having none others sides with < 30,<60 and <90?
Hmmm. Could you reword this question?
To find the sides of a right triangle when only one angle is given, you can use trigonometric ratios. In this case, since the angles given are less than 90 degrees, we can use the sine, cosine, or tangent ratios.
Let's assume that the angle < 30 degrees is opposite to side A, the angle < 60 degrees is opposite to side B, and the angle < 90 degrees is opposite to side C, which represents the hypotenuse.
1. To find side A:
- Use the sine ratio: sin(30) = A/C
- Rearrange the equation to solve for A: A = C * sin(30)
2. To find side B:
- Use the sine ratio: sin(60) = B/C
- Rearrange the equation to solve for B: B = C * sin(60)
3. To find side C:
- Since side C is the hypotenuse and opposite the right angle, you can use the Pythagorean theorem: C^2 = A^2 + B^2
- Rearrange the equation to solve for C: C = sqrt(A^2 + B^2)
Remember, the value of C is essential in step 1 and step 2, as it is needed to find sides A and B respectively.
Once you know the values of A, B, and C, you will have the lengths of all the sides of the right triangle.