I'm having a few troubles on my equations. I have to write the neutralisation reaction equation between Acetic Acid and Sodium Hydrogen Carbonate

Question

I'm having a few troubles on my equations. I have to write the neutralisation reaction equation between Acetic Acid and Sodium Hydrogen Carbonate

I've gotten this far, but I don't if its the right way to do it

CH3COOH + NaHCO3 ---->>> (salt) + H2O

I don't know what to put in the salt part. Í don't if its right, because I heard my friend say something about excluding the spectator ions.

Answer 1

I can't seem to figure out my next question either.

Neutralisation between Acetic Acid and Sodium Carbonate.

CH3COOH + Na2CO3 --->>>> (salt) + H2O

I really hope someone can help me. Thanks.

Answer 2

Memorize this: Acids and carbonates yield water, a salt, and carbon dioxide.

Answer 3

To write the neutralization reaction equation between acetic acid (CH3COOH) and sodium hydrogen carbonate (NaHCO3), let's break down the components and determine the products formed.

First, identify the acid (acetic acid) and the base (sodium hydrogen carbonate). In a neutralization reaction, an acid reacts with a base to form a salt and water.

The chemical formula for acetic acid (CH3COOH):
CH3COOH

The chemical formula for sodium hydrogen carbonate (NaHCO3):
NaHCO3

Now, let's focus on the reactants:
Acetic acid (CH3COOH) + Sodium hydrogen carbonate (NaHCO3)

The general guideline to represent the reaction is:

Acid + Base → Salt + Water

To form the salt, we need to consider the ions present in the reactants. In this case, the sodium ion (Na+) and the hydrogen carbonate ion (HCO3-) combine to form the salt. The sodium ion comes from the base (NaHCO3), and the hydrogen carbonate ion comes from the acid (CH3COOH).

Using this information, we can write the neutralization equation as:

CH3COOH + NaHCO3 -> CH3COONa + H2O + CO2

In this equation, the salt formed is sodium acetate (CH3COONa), water (H2O), and carbon dioxide (CO2).

Regarding your friend's comment about excluding spectator ions, spectator ions are ions that appear on both sides of the reaction equation and do not directly participate in the reaction. In this case, sodium ion (Na+) is a spectator ion since it appears on both sides. If you wish to exclude the spectator ions, the simplified equation would be:

CH3COOH + HCO3- -> CH3COO- + H2O + CO2

In this equation, the salt formed is acetate (CH3COO-), water (H2O), and carbon dioxide (CO2).

Both equations are correct, but the second equation excludes the spectator ion.