posted by Damien Patel .
The first step of the synthesis is described by the reaction below. When 1.750 g of Fe(NH4)2(SO4)2 6H2O is mixed with 13 mL of 1.0 M H2C2O4 , the theoretical yield of FeC2O42H2O is
Fe(NH4)2(SO4)26H2O(s) + H2C2O4(aq)
FeC2O42H2O(s) + (NH4)2SO4(aq) + H2SO4(aq) + 4 H2O(l)
Please help me. I tried everything. =(
*Convert 1.750g of Fe(NH4)2(SO4)2•6H2O to moles by dividing by the molar mass of this compound.
*Find the moles of H2C2O4 using:
moles = (liters)(mol/L)
Te moles ratio of the two reagents id 1 to 1. That means that the smaller number of moles belongs to the limiting reagent.
To get the theoretical yield of FeC2O42H2O, multiply the moles of the limiting reagent by the molar mass of this product.