math
posted by alicia .
Solve for x (without using a calculator):
log base 3 of x^2= 2log base 3 of 44log base 3 of 5
Solve each of the inequalities:
(a) x^2+2x3<(or equal to)0
(b) (2x1)/(3x2)<(or equal to)1
Any help is appreciated!

log base(3)x^2 = 2log(3)4  4log(3)5
= log(3)[4^2/5^4]
Therefore x^2 = 16/625
x = 4/25 = 0.16 
<<(a) x^2+2x3<(or equal to)0 >>
First solve
x^2 +2x 3 =0
(x+3)(x1) = 0
x = 3 or 1
Between those points, for example at x=0, the function is negative.
(f(0)= 3, for example.)
3 <_ x <_ 1 is the answer 
<<(2x1)/(3x2)<(or equal to)1>>
When equal to 1,
2x1 = 3x2
x = 1
If you go on the positive side if 1, for example at x = 2,
(2x1)/(3x2) = 3/5 which is <1
Any x >_ 1 satisfies the inequality
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