Math
posted by David .
Simplify:
24w^7t^4/6w^9t^2
And How Exactly do u do this?
I got 4w^16t^6

(24w^7*t^4)/(6w^9*t^2)
The answer is 4 t^2/w^2
You have to apply the rule
x^a/x^b = x^(ab)
to the exponent terms
Respond to this Question
Similar Questions

math
(2w1)^2=4(w3)^2 Expand both sides of the equation, then simplify: 4w^1  4w + 1 = 4w^2  24w + 36 ...... ..... w = 7/4 
simplify
i need to simplify : does this mean just do the problems; here is what i got for 4 problems below: are they right? 
math
can you check if i did these 3 problems right or not: 5 (a+2) i got: 3 simplify: 5 (x+2) i got: 3 simplify: (y3) (4) i got: 12 
Math
Here are the questions I need help with, please help. [(1/4)^3 divide sign (1/4)^2]^2 I got (1/4)^10 but I got it wrong (3^1/2)^3 _______ I got 1/216 9 (56r^2)divide sign (7r^2)= I got 8r x(y)(x)(2y) (12) (10xy^3) (3x^2y^2) (5x) … 
Math Ms. Sue
Here are the questions I need help with, please help. [(1/4)^3 divide sign (1/4)^2]^2 I got (1/4)^10 but I got it wrong (3^1/2)^3 _______ I got 1/216 9 (56r^2)divide sign (7r^2)= I got 8r x(y)(x)(2y) (12) (10xy^3) (3x^2y^2) (5x) … 
Math Please Urgent
Here are the questions I need help with, please help. [(1/4)^3 divide sign (1/4)^2]^2 I got (1/4)^10 but I got it wrong (3^1/2)^3 _______ I got 1/216 9 (56r^2)divide sign (7r^2)= I got 8r x(y)(x)(2y) (12) (10xy^3) (3x^2y^2) (5x) … 
math
A diver on a platform 40 feet in height jumps upward with an initial velocity of 5ft/s. His height in h feet after t seconds is given by the function h=16t^2+5t+50. a. What is his maximum height? 
Math
I need help solving these problems y=0.4x^2+8.3x+4.3 I got 0.52 h=16t^2+149t+30 I got 640.5 feet after 4.63 seconds 0=x^2+3x10 I got x=5, 2 (2x4)(2x1)=0 I got 2, 1/2 x^2+8x=10 I got 1.1, 9.1 HELP PLEASE 
MathASAP please
1. (10x^3 + 30x 20) divided by (5x+5)? 
Math
5.Simplify x/6xx^2 a)1/6x ; where x=0.6 b) 1/6x; where x=6*** c)1/6x; where x=0 d)1/6 6. 5x^3/7x^3+x^4 a)5/7+x; where x= 0,7**** b)5/7+x; where x=7 c)5/7x; where x=0 d)5/7 7.x2/x^2+4x12 a)1/6+x; where x=6*** b)1/6+x; where …