A balloon filled with helium has a volume of 30.0 L at a pressure of 100 kPa and a temperature of 15 degrees C. What will the volume of the balloon be if the temperature is increased to 80 degrees C and the pressure remains constant?

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To solve this problem, we can use the combined gas law equation:

P1V1 / T1 = P2V2 / T2

Where:
P1 = initial pressure = 100 kPa
V1 = initial volume = 30.0 L
T1 = initial temperature in Kelvin = 15 + 273.15 = 288.15 K
T2 = final temperature in Kelvin = 80 + 273.15 = 353.15 K
P2 = final pressure = 100 kPa (constant)

Let's substitute the values into the equation and solve for V2:

(100 kPa)(30.0 L) / (288.15 K) = (100 kPa)(V2) / (353.15 K)

Now, let's solve for V2:

(100 kPa)(30.0 L)(353.15 K) = (288.15 K)(100 kPa)(V2)

10,594,500 kPa*L = 28,815,000 kPa*L * V2

V2 = (10,594,500 kPa*L) / (28,815,000 kPa*L) = 0.367 L

Therefore, the volume of the balloon will be approximately 0.367 L when the temperature is increased to 80 degrees C while the pressure remains constant.

To find the volume of the balloon when the temperature is increased to 80 degrees C while the pressure remains constant, we need to use the combined gas law equation. The combined gas law relates the initial and final conditions of a gas sample when pressure, volume, and temperature change.

The combined gas law equation is:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

Where:
P1 and P2 are the initial and final pressures, respectively.
V1 and V2 are the initial and final volumes, respectively.
T1 and T2 are the initial and final temperatures, respectively.

In this case, we have the following values:
P1 = 100 kPa (constant pressure)
V1 = 30.0 L
T1 = 15 degrees C = 15 + 273.15 K (temperature in Kelvin)

We want to find V2 when T2 = 80 degrees C = 80 + 273.15 K.

Plugging in the values into the combined gas law equation:

(100 kPa * 30.0 L) / (15 + 273.15 K) = (100 kPa * V2) / (80 + 273.15 K)

Now we solve for V2:

(100 kPa * V2) = (100 kPa * 30.0 L * (80 + 273.15 K)) / (15 + 273.15 K)

V2 = [(100 kPa * 30.0 L * (80 + 273.15 K)) / (15 + 273.15 K)] / (100 kPa)

Simplifying the equation:

V2 = (30.0 L * (80 + 273.15 K)) / (15 + 273.15 K)

Calculating the values:

V2 = (30.0 L * (353.15 K)) / (288.15 K)

V2 = (30.0 L * 353.15) / 288.15

V2 ≈ 36.77 L

Therefore, the volume of the balloon will be approximately 36.77 L when the temperature is increased to 80 degrees C while the pressure remains constant.

Use P1V2 = P2V2 since T is constant.