Need help,
Farmer Billybob is building a fence to keep his prize goats. He wants to make the legth twicw as large as the width. Now, he has 42 yards of fencing to use. What are the dimensions of the fence for his goats?
Let x = the width and solve for x:
x + x + 2x + 2x = 42
6x = 42
x = 7
The width is 7 yards. What is the length?
14
Right!
The dimensions of the yard are 7 yards by 14 yards.
how many feet of fencing must be used to enclose a rectangular space that is 30 yards long and 28 feet wide?
To find the dimensions of the fence, we need to solve the problem step by step.
Let's assume the width of the fence is "w" yards. According to the problem statement, the length of the fence is twice the width. So, the length would be "2w" yards.
The perimeter of a rectangle (fence) is given by the formula: Perimeter = 2(width + length).
In this case, the perimeter is given as 42 yards, so we can set up the equation as follows:
42 = 2(w + 2w)
Now, let's simplify and solve for "w":
42 = 2(3w)
Divide both sides by 2:
21 = 3w
Divide both sides by 3:
w = 7
Therefore, the width of the fence is 7 yards. As the length is twice the width, the length of the fence is 2 * 7 = 14 yards.
So, the dimensions of the fence for Farmer Billybob's goats are 7 yards (width) by 14 yards (length).