what is the balanced equation for the reaction that takes place between bromine and sodium iodide
Br2 + 2 NaI -> I2 + 2 NaBr
thank you very very very much
The balanced equation for the reaction between bromine (Br2) and sodium iodide (NaI) is:
Br2 + 2NaI → 2NaBr + I2
In this reaction, bromine (Br2) reacts with sodium iodide (NaI) to produce sodium bromide (NaBr) and iodine (I2).
To find the balanced equation for the reaction between bromine and sodium iodide, we need to first determine the products of the reaction.
Bromine (Br2) is a diatomic molecule, meaning it exists as two bromine molecules bonded together. Sodium iodide (NaI) is composed of sodium (Na) cations and iodide (I-) anions.
In this reaction, bromine will replace iodine to form sodium bromide (NaBr), and iodine will be freed. The balanced equation can be determined as follows:
Br2 + 2 NaI → 2 NaBr + I2
In this equation, two bromine molecules react with two sodium iodide molecules, resulting in the formation of two sodium bromide molecules and one iodine molecule.
To balance the equation, we need to ensure that the same number of atoms of each element is present on both the reactant and product sides. In this case, there are two bromine atoms on both sides, two sodium atoms on both sides, and two iodine atoms on both sides, making the equation balanced.