According to a rating agency, a car's MPG (miles per gallon) ratings are: 25 MPG for city and 30 MPG for highway driving. A driver spent $20.00 (the gasoline costs $1.25/gallon) on a combined city and highway trip of 450 miles. How many miles "C" in city and "H" on highway was the car driven ?

I need to get two equations out of this and use the substitution or elimination method to solve this problem.

Let C = 450 - H

$1.25 (30H + 25C) = $20

Substitute the value of C in the first equation into the second. Solve for H. Put value of H into the first equation to solve for C. Check by putting both values into the second equation.

I'll let you do the calculations. I hope this helps. Thanks for asking.

To solve this problem, we need to set up two equations and use the method of substitution or elimination. Let's start by assigning variables to the unknowns:

Let's say "C" represents the number of miles driven in the city, and "H" represents the number of miles driven on the highway.

We can use the given MPG ratings to calculate the total gallons of gasoline consumed. Since we know the cost per gallon ($1.25), we can determine the total cost of the trip.

Equation 1: Gasoline cost equation
The total cost ($20.00) is equal to the cost per gallon ($1.25) multiplied by the total gallons consumed. The total gallons consumed can be calculated by dividing the total miles driven by the combined MPG rating.

Total cost = Cost per gallon x Total gallons consumed
$20.00 = ($1.25/gallon) x (C + H) / (25 MPG + 30 MPG)

Simplifying the equation further, we get:
20 = 1.25(C + H) / 55

Equation 2: Distance equation
The total distance traveled is equal to the sum of the miles driven in the city and on the highway.

Total distance = Miles driven in city + Miles driven on highway
450 miles = C + H

Now we have two equations:
Equation 1: 20 = 1.25(C + H) / 55
Equation 2: 450 = C + H

You can now use the method of substitution or elimination to solve these equations simultaneously and find the values of "C" and "H."