If you have the equation y=-1/2x-4
How would you set up a table for the equation for x, y (xy)?
Do you mean
a) y = [-1/(2x)] -4
or
b) y = -(1/2)x - 4
or
c) y = -1 / (2x-4)
????????????????????????
It is a table with x in the first box at the top y is in the second box and (xy) is the third box. Now under each varable you are supposed to complete the table using the equation. There are 5 rows down under each varable.
x y (xy)
______-1______________
-2____________________
______-4______________
2____________________
8____________________
Then solve for x, y and (x,y)
But I do not know what your equation is. Do you mean a, b, or c ?
if it is b then
y = -(1/2)x - 4 is the same as x = -2(y+4)
now if y = -1 is given
then x = -6
and xy = 6
if x = -2 is given
then y = -3
and xy = 6
if y = -4 is given
then x = 0
and xy = 0
etc
To set up a table for the equation \(y=-\frac{1}{2}x-4\), we need to choose a few values for \(x\) and determine the corresponding values for \(y\). Here's how to go about it step by step:
1. Choose a few values for \(x\). Let's select -4, -2, 0, 2, and 4.
2. Substitute each \(x\) value into the equation to find the corresponding \(y\) value. Start with \(x = -4\):
\(y = -\frac{1}{2}(-4) - 4 = 2 - 4 = -2\)
\(x = -2\):
\(y = -\frac{1}{2}(-2) - 4 = 1 - 4 = -3\)
\(x = 0\):
\(y = -\frac{1}{2}(0) - 4 = 0 - 4 = -4\)
\(x = 2\):
\(y = -\frac{1}{2}(2) - 4 = -1 - 4 = -5\)
\(x = 4\):
\(y = -\frac{1}{2}(4) - 4 = -2 - 4 = -6\)
3. Now, we can create the table. Write down the selected values of \(x\) and their corresponding \(y\) values as follows:
\(\begin{array}{|c|c|}
\hline
x & y \\
\hline
-4 & -2 \\
-2 & -3 \\
0 & -4 \\
2 & -5 \\
4 & -6 \\
\hline
\end{array}\)
And that's how you set up a table for the equation \(y=-\frac{1}{2}x-4\).