posted by Claire .
Two charges separated by one meter exert 1 Newton forces on each other. If the magnitude of each charge is doubled, the force on each charge is ______ Newtons.
Coulomb's Law is:
F = kQ1*Q2 / d^2
k is a constant
Let's represent each charge as "q"
then the intial force F1 is:
F1 = k*q*q / 1^2 = kq^2
doubling the charge, the new force, F2, is:
F2 = k(2q)(2q) / 1^2 = 4kq^2
F2 is how many times bigger than F1?
4 times bigger - so I think the answer would be 4 Newtons.