algebra
posted by Frnciois .
The stopping distance d of a car after the brakes have been applied varies directly as the square of the speed r. if the car traveling 70mph cab stop in 270ft, how many feet will it take the same car to stop when it 1s traveling 50 mph

Stopping distance = C r^2
270 = C*70^2
C = 270/70^2
At 50 mph,
stopping distance = 50^2*270/(70^2)
= (5/7)^2 * 270 ft = ?