trig/pre calc
posted by brandy .
hello, i don't quite understand how to do this type of problem:
1. find the exact value of sin (pi/3).
even more confusing is
2. find the exact value of csc^1 (1).
i would appreciate any kind of help! thank you!

I normally like to replace pi with 180.
So...
sin(pi/3)
= sin(180/3)
= sin(60)
What is sin(60)? sqrt(3)/2
As for csc^1(1), I like to think of this as its inverse, 1/sin^1(1). Where in the unit circle is sin=1? That is, where is y=1? 90 degrees 
Since they seem to want angles to be expressed in radians, it might be better to give pi/2 as the answer to csc^1(1) . 90 degrees is also correct, of course.
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