Team X and Team Y have a tug of war. From their starting positions Team X pulls Team Y forward 3 meters, and Team X is then pulled forward 5 meters. Team Y then pulls Team X forward 2 meters. If the first team to be pulled forward 10 meters loses, how many more meters must Team Y pull Team X forward to win?

Please answer ASAP! I'm leaving in 5 minutes

To solve this problem, we can keep track of the distance each team is being pulled forward and determine when one team reaches 10 meters. Let's break it down step-by-step:

1. Team X pulls Team Y forward 3 meters. Now Team Y is at -3 meters (pulled backward) and Team X is at 3 meters.

2. Team X is then pulled forward 5 meters. Now Team Y is still at -3 meters, but Team X is at a total of 8 meters (3 + 5).

3. Team Y then pulls Team X forward 2 meters. Now Team Y is at -1 meter (-3 + 2) and Team X is at a total of 10 meters (8 + 2).

Since Team X has reached a total of 10 meters, they have lost the game. Thus, Team Y has won.

Since Team Y has already won, there is no need to calculate how many more meters Team Y must pull Team X forward.

dfd

do the algebra. Team X is +3, then -5, ten -2, for a net -4, So.....