# Math

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A 10-gal aquarium is 3 in. higher than it is wide. Its length is 21 in, and its volume is 2730 in^3. What are the height and width of the aquarium?

x(x+3)......x^2+3x
21(x^2+3x)....
21x^2+63x-2730.....

I am stuck.....I think I am doing it wrong. I have the answers but I don't know how to get there....Help!

• Math -

Let x be the width. x = 3 is then the height.

21 x*(x+3) = 2730
x(x+3) = 130
x^2 +3x -130 = 0
(x-10)(x+13) = 0

The only meaningful root is x = 10.

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