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An 8.00 g bullet is fired into a 180 g block that is initially at rest at the edge of a table of 1.00 m height. The bullet remains in the block, and after the impact the block lands d = 2.2 m from the bottom of the table. Determine the initial speed of the bullet.

  • physics -

    initial momentum = final momentum
    .008 * V + .18 * 0 = .188 U
    where V is initial bullet speed and U is horizontal speed off the table.
    Now get U
    t is fall time
    horizontal distance = U t = 2.2
    vertical distance = 4.9 t^2 = 1
    t= sqrt (1/4.9)
    solve that for t
    U = 2.2 / t
    V = (.188/.008) U

  • physics -

    420

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