# algebra

posted by .

do I do this correct and if not can you please show and tell me what I did wrong? thank you

6x^2-7x=3
We have to move the 3 to the left so it becomes
6x^2-7x-3=0
6x^2-7x-3=0 this makes this a quadratic equations 6*x^2-7*x-3=0 and has the answer of 1.5,-0 so
0=0
solution is x=1.5, x= -0.3333333333

• algebra -

I don't get the 0=0 step but your solution is correct for x = 1.5 and x = -0.3333.

• algebra -

so can you please show me what i am doing wrong with this?

• algebra -

I don't know that you did anything wrong. How did you solve the quadratic? Did you use the quadratic formula?

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