What roots does x^3 - 6x^2+3x-10 have?
Solve for the first root by graphing, using the "p/q rule", or trial and error. I will try the latter.
By inspection, I see that one root of the equation
x^3 - 6x^2+ 3x -10 = 0
is x = -1. Therefore (x+1) is a factor
Now divide x+1 into x^3 - 6x^2+ 3x- 10 using polynomial long division and get a quadratic that must be zero. I get
x^2 -7x -10 = 0. Factor that for the remaining roots