damon please help (: !
posted by margie (: .
1. 2x > 6 and x  4 < 3
2. x + 3 > 2x + 1 and 4x < 8
3. 6 < x + 3 < 6
4. 3x > 6 or x  5 < 2
5. x  2 > 2x + 1 or 10 > 2x + 2

LOL  why me ?
1. 2x > 6 and x  4 < 3
x > 3 and x < +7
3 < x < +7 
2. x + 3 > 2x + 1 and 4x < 8
note if you divide by negative number, change arrow direction
2 > x and x > 2 can not be both 
3. 6 < x + 3 < 6
subtract 3 from everything
9 < x < 3 
'cause you rock (: !
thanks for helping me so far (: 
4. 3x > 6 or x  5 < 2
x < 2
or x < 7
everything left of seven satisfies the second, everything left of 2 satisfies both. In other words x<2 is a subset of x <7 
5. x  2 > 2x + 1 or 10 > 2x + 2
x < 2 or x > 4
that is everywhere
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