# alg 2

posted by .

find all zeros of the following function:
f(x)=x^3-x^2+4x-4
I have (x^2+4)(x+1)

so one zero is 1. how do i find the two other zeros.

• alg 2 -

if +1 is a zero, (x-1) is a factor because (x-1) is zero when x = 1

• alg 2 -

I have
(x^2+4)(x-1)
then when is (x^2 + 0 x +4 )= 0??
x = [ 0 +/- sqrt (0 -16) ] / 2
x = +/- 2 i (imaginary roots)

## Similar Questions

1. ### Decartes Rule of Signs

Could you explain to me decartes Rule of signs?
2. ### alg 2

given that one of the zeros of the funiction f(x)=x^3-8x^2+11x+20 is -1, find the sum of the other zeros. hwo do i do this?
3. ### math

Find all the zeros of the function. f(x) = x^3 + 11x^2 + 39x + 29 I found one of the zeros = -1 but I am confused on how to find the other two.
4. ### Math

For what values of k does the function f(x)=(k+1)x^2+2kx+k-1 have no zeros?
5. ### calculus

For the following function f(x)=2x^4-6x^2+2x-1. Find the maximum number of real zeros and Use Descartes's rule of signs to determine how many positive and how many negative zeros the function has. You do not need to find the zeros.
6. ### math

usethe rational zero theorem to find all real zeros of the polynomisl function.Use the zeros to factor f over the real numbers. f(x)=x^4+2x^33-7x^2-8x+12 what are the real zeros?
7. ### alg 2

list all the possible rational zeros of f using the rational zero theorem. Then find all the zeros of the function. f(x)=x^3+4x^2+9x+36
8. ### Math

The function f(x)=x^2+5x+6 has zeros at -2 and -3. What are the zeros of the function y=-2f(x/11) ?
9. ### algebra

Using the rational zeros theorem to find all zeros of a polynomial The function below has at least one rational zero. Use this fact to find all zeros of the function g(x)=5x©ù-28©ø-48x©÷-8x+7 if more than one zero, separate with …
10. ### algebra

Using the rational zeros theorem to find all zeros of a polynomial The function below has at least one rational zero. Use this fact to find all zeros of the function h(x)=7x^4-9x^3-41x^2+13x+6 if more than one zero, separate with commas. …

More Similar Questions