Vectors
posted by Sam .
Vectors a and b have magnitudes 2 and 3, respectively. If one of them is 50degrees, find the vector 5a2b and state its magnitude.

Use the law of cosines: You know two sides, and the included angle.
Draw the figure before you compute. 
I tried that but it doesn't work.
I did (5)(2^2)+(2)(3^2)(2)(2)(3)cos50. 
vector 5a has magnitude 10 and call it at 50 degrees
vector 2 b has magnitude 6 and call it at 0 degrees
so our triangle is
10 and 6 with fifty degrees between them
so the magnitude we are looking for is from
c^2 = 10^2 + 6^2  10*6*cos 50
that is why it did not work. 
At what angle should be adjusted the two vectors to have the same value of their llA+Bll and llABll?