I am trying to solve a problem using Newton's equation, which is (-1/2)(9.8)t^2+ vot+ h. The problem says that a car rolls of a 120 foot high cliff. I know how to right the equation for this problem which would be (-1/2)(9.8 m/s) t^2 + vot + 37m. I am trying to find out how high the car will befter 2 seconds.

Question

I am trying to solve a problem using Newton's equation, which is (-1/2)(9.8)t^2+ vot+ h. The problem says that a car rolls of a 120 foot high cliff. I know how to right the equation for this problem which would be (-1/2)(9.8 m/s) t^2 + vot + 37m. I am trying to find out how high the car will befter 2 seconds.

Answer 1

well, when it starts off the cliff it may have horizontal velocity but has no vertical velocity so Vo = 0

(1/2) * 9.8 = 4.9 so we might write that as
z = -4.9 t^2 + 0 + 37
so after two seconds we have:
z = -4.9 * 4 + 37
z = 37-19.6
or 17.4 meters above ground
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by the way, the vertical velocity would be:
V = Vo - 4.9 t
V = 0 - 9.8
or 9.8 meters per second down
The horizontal velocity would be whatever horizontal velocity it started with because there is no acceleration in the horizontal plane, only vertical.

Answer 2

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by the way, the vertical velocity would be:
V = Vo - 9.8 t
V = 0 - 19.6
or 19.6 meters per second down
The horizontal velocity would be whatever horizontal velocity it started with because there is no acceleration in the horizontal plane, only vertical.

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Answer 3

Thank you.

Answer 4

To find out how high the car will be after 2 seconds using Newton's equation, you need to substitute the given values into the equation and solve for the height.

Here's how you can do it step by step:

1. Start with Newton's equation:
(-1/2)(9.8 m/s^2) t^2 + vot + h

2. Substitute the values into the equation:
Since the car rolls off a 120-foot cliff, the initial height (h) is 120 feet. Also, since we're working with meters per second in the equation, you need to convert the initial velocity (vo) from feet per second to meters per second. Let's assume the conversion factor is 0.3048 meters per foot.

So, the equation becomes:
(-1/2)(9.8 m/s^2) t^2 + (vo)(0.3048 m/s)(t) + 37 m

3. Substitute the time value into the equation:
Plug in t = 2 seconds:
(-1/2)(9.8 m/s^2) (2 s)^2 + (vo)(0.3048 m/s)(2 s) + 37 m

4. Simplify and solve:
(-1/2)(9.8 m/s^2)(4 s^2) + (vo)(0.3048 m/s)(2 s) + 37 m

Now, you can calculate the result using the given values.

After performing the calculations, you should be able to determine how high the car will be after 2 seconds based on the given equation.