posted by Ken .
The rate constant for a reaction at 305.0 K is two times the rate constant at 295.0 K. The activation energy of the reaction is ______ kJ mol
Use the Arrhenius equation.
I can use the Arrhenius equation when it is straight forward, but when it is in a question like this, I start to get lost.
The part that is confusing you PROBABLY is the part about 1 rate being twice the other one. So for the ln k2/k1 part, just use k1 and 2*k1 for the numbers. OR, just make up a number like 6 for one of them, then 12 will be the other one.