Solve by elimination.
15x+10y=-20
3x+2y=-4
multiply second equation by 5 and you will get
15x + 10y = -20
which is the same as the first equation.
So you are trying to solve an equation with itself.
There will be an infinite number of solutions.
To solve the given system of equations by elimination, the goal is to eliminate one variable by adding or subtracting the equations together. Let's go step by step:
Step 1: Multiply the second equation by 5 to make the coefficients of the x-terms the same as the coefficients of the x-term in the first equation. This will allow us to eliminate the x variable when we add the equations together.
15x + 10y = -20 (Equation 1)
3x + 2y = -4 (Equation 2)
Multiply Equation 2 by 5:
5*(3x + 2y) = 5*(-4)
15x + 10y = -20 (Equation 1 - unchanged)
15x + 10y = -20 (Equation 2 - after multiplication)
Now we have two equations with the same coefficient for the x-term, which is 15x.
Step 2: Subtract Equation 2 from Equation 1. This eliminates the x variable.
(15x + 10y) - (15x + 10y) = (-20) - (-20)
Simplifying, we get:
0 = 0
This means that the two equations are dependent (i.e., they represent the same line), and there are infinitely many solutions.
The solution to the system of equations is any ordered pair (x, y) that satisfies the original equations.