What are the formulas for the following:
A. Tetrachloroferrate(II) ion
B.Pentammineaquaruthenium(III) ion
Thank you!
Just write it the way the name tells you.
Tetrachloro means 4 chlorine atoms. Ferrate(II) means iron with a valence of 2.
Then you must put a charge on it.
FeCl4^-2 (iron has a valence of +2, each Cl has a valence of -1 for a total of -4; +2 and -4 = -2 for the ion).
Ru(NH3)5(H2O)+3
thank you
To determine the formulas for the given ions, we need to understand the naming conventions for coordination compounds.
A. Tetrachloroferrate(II) ion:
In this case, "tetrachloro" indicates that there are four chlorine atoms bonded to the central metal ion. "Ferrate" refers to the central metal ion being iron (Fe). The charge on the ion is 2-. To determine the formula, we combine the symbol for the central metal ion (Fe) with the formula for the ligands (chlorine, Cl), along with the charge on the ion.
Therefore, the formula for tetrachloroferrate(II) ion is FeCl4^2-.
B. Pentammineaquaruthenium(III) ion:
In this case, "penta" indicates that there are five ammine (NH3) ligands bonded to the central metal ion. "Aqua" indicates the presence of one water (H2O) ligand. "Ruthenium" refers to the central metal ion being ruthenium (Ru). The charge on the ion is 3+.
Therefore, the formula for pentammineaquaruthenium(III) ion is [Ru(NH3)5(H2O)]^3+.