name the 2 digit multiple of 8 who digits add up to 10
If you are seeking an algebraic approach:
1--8x = 10A + B
2--A + B = 10
3--8x = 10A + 10 - A
4--8x = 9A + 10
5--8x - 9A = 10
6--Dividing by the lowest coefficient, yields x - A - A/8 = 1 + 2/8
7--(A + 2)/8 must be an integer k making A = 8k - 2
8--Substituting back into (4) yields x = 9k - 1
9--Clearly, k can only be 1 as k = 0 yields negative results and k = 2 or more yields 2 digit values for A and B.
10--Thus, for k = 1, x = 8, A = 6 and B = 4 yielding 8(8) = 64 where 6 + 4 = 10.
Name the 2 digit multiple of 8 whose digits add up to 10
To find the two-digit multiples of 8 whose digits add up to 10, we can follow these steps:
1. Start by listing the multiples of 8:
- 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, 112, 120, 128, 136, 144, 152, 160, and so on.
2. Calculate the sum of the digits for each multiple of 8:
- For example, the sum of the digits for 8 is 8.
- The sum for 16 is 1 + 6 = 7.
- The sum for 24 is 2 + 4 = 6.
- And so on...
3. We're looking for multiples whose digits add up to 10. Scanning through the list, we find that the only two-digit multiple of 8 whose digits add up to 10 is 80 (8 + 0 = 8).
Therefore, the two-digit multiple of 8 whose digits add up to 10 is 80.
Here are the 2-digit-multiples of 8:
16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96
Which of those has digits that add up to 10?