which inequality is true if x=3.04/1.48, y = 1.99+0.33, and
z = (1.3)^3?
answer is either:
y<z<x
y<x<z
x<z<y
x<y<z
use your calculator to evaluate x, y and z
once you have all 3 as decimals, it should be easy to determine the correct answer.
To determine the correct inequality among the given options, let's first evaluate the values of x, y, and z.
Given:
x = 3.04/1.48
y = 1.99 + 0.33
z = (1.3)^3
Now, let's calculate the values:
x = 3.04/1.48 ≈ 2.054
y = 1.99 + 0.33 = 2.32
z = (1.3)^3 ≈ 2.197
Now that we have calculated the values, let's compare them to find the correct inequality.
y < z < x
Therefore, the correct inequality is y < z < x.