how do i graph this...
x^2=-8y
y = -(1/8) x^2
vertex at (0,0)
opens down
x^2 always + so same y for -x and +x
This is very similar to your last question.
x^2=-8y
vertex at (0,0)
opens down
x^2 always + so same y for -x and +x
This is very similar to your last question.