posted by Elisa
Two packing crates of masses m1 = 10.0 kg and m2 = 3.50 kg are connected by a light string that passes over a frictionless pulley as in Figure P4.26. The 3.50 kg crate lies on a smooth incline of angle 37.0°. Find the acceleration of the 3.50 kg crate.
up the incline:
Find the tension in the string.:
You will have to describe figure P4.26
Is the 10 kg mass hanging straight down?
Is the 3.50 kg mas being pulled up an incline as the 10 kg mass falls?
Assuming that the situation is as I described, call the string tension T and the acceleration a
First the 10 kg mass falling
m g - T = m a
98 - T = 10 a
Now the 3.5 kg mass sliding up the incline.
T - m g sin 37 = m a
T - 20.6 = 3.5 a
add the two
98 - 20.6 = 10 a + 3.5 a
77.4 = 13.5 a
a = 77.4/13.5
The figure shows m1 going straight down and m2 on an incline.