q:The electricity revised at an electric substation has a potential difference of 2.80 10^5V, if the required output is 440 V. what should be the ratio of the turns of the step-down transformer?
a: 28000/440= 636
correct. Voltage is in direct proportion to the turns. Actually, it would be better written as 636/1 or 636:1, since it is a ratio
thanks!
thank you as well. I doubted myself on this problem and whether or not the rate was proportionate to the turns and voltage. Thank you for clarifying it.
To find the ratio of the turns of the step-down transformer, we need to use the formula:
V2/V1 = N2/N1
Where:
V1 is the potential difference of the electricity at the electric substation (given as 2.80 x 10^5 V)
V2 is the required output potential difference (given as 440 V)
N1 is the number of turns on the primary (input) side of the transformer (unknown)
N2 is the number of turns on the secondary (output) side of the transformer (unknown)
We can rearrange the formula to solve for the ratio of the turns:
N2/N1 = V2/V1
Substituting the given values, we have:
N2/N1 = 440 / (2.80 x 10^5)
Now we can calculate the ratio of the turns:
N2/N1 ≈ 0.0015714286
To simplify this ratio, we can multiply both sides by a common factor to get whole numbers. In this case, multiplying by 1000 gives:
N2/N1 ≈ 1.5714286
And rounding to the nearest whole number:
N2/N1 ≈ 2
Therefore, the ratio of the turns of the step-down transformer should be approximately 2.