a gas volume has of v1=450ml. if the temp is held constant, what volume would gas occupy if the pressure p2=2p1?
omg i cant figure anything out!!!!!!!!
P1V1 = P2V2.
Just make up a number for P1. Call it anything, say 10 atm.
Then P1 = 10 atm
V1 = 450 mL
P2 = 2*P1 = 2*10 = 20 atm.
V2 = ??
It makes it a much simpler problem if you do that. You CAN (but I think it makes it harder) just use
P1 = P1
V1 = 450 mL
P2 = 2*P1
V2 = ??
Then P1*450 = 2*P1*V2
Solving for V2 gives
V2 = P1*450/(2*P1) = 450/2 = 225 mL. You see the P1 cancels which is WHY we can use any number we choose and it doesn't matter which number we choose.
Doing it the other way gives us
10*450=20*V2
V2 = 10*450/20
V2 = 4500/20 = 225 mL.
THANNXX YOU SHOULD HONESTLY BE MY TUTOR LOL
Don't worry, I'm here to help! To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.
According to Boyle's Law:
P1 * V1 = P2 * V2
Where P1 and V1 are the initial pressure and volume, respectively, and P2 and V2 are the final pressure and volume, respectively.
Given that P2 = 2P1 and V1 = 450 ml, we can substitute these values into the equation:
P1 * V1 = P2 * V2
P1 * 450 ml = (2P1) * V2
By dividing both sides of the equation by P1, we get:
450 ml = 2V2
To isolate V2, we divide both sides of the equation by 2:
V2 = 450 ml / 2
V2 = 225 ml
Therefore, if the pressure doubles while the temperature is held constant, the volume of the gas will become 225 ml.
To find the volume that a gas would occupy if the pressure is doubled, you can use Boyle's Law. Boyle's Law states that at a constant temperature, the product of pressure and volume is a constant.
Mathematically, Boyle's Law can be expressed as:
P1 * V1 = P2 * V2
Where:
P1 = Initial pressure
V1 = Initial volume
P2 = Final pressure (2 times the initial pressure)
V2 = Final volume (what we want to find)
Let's plug in the given values:
P1 = Initial pressure = unknown
V1 = Initial volume = 450 ml
P2 = Final pressure = 2 * P1
V2 = Final volume = unknown
Since the temperature is held constant, we can assume it is the same for both initial and final conditions.
Using Boyle's Law equation:
P1 * V1 = P2 * V2
Substituting the given values:
P1 * 450 ml = (2 * P1) * V2
We can simplify this equation to solve for V2:
450 ml = 2 * V2
Divide both sides of the equation by 2:
V2 = 450 ml / 2
Calculating the value:
V2 = 225 ml
Therefore, if the initial pressure is doubled, the gas would occupy a volume of 225 ml.