algebra

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1/9 -K+3/72k = 1/9k - k-1/8k
i can't figure out how to get rid of the denominators

  • algebra -

    It is very important to use brackets.
    I will assume you meant

    1/9 -(K+3)/(72k) = 1/(9k) - (k-1)/(8k)

    multiply each term by 72k to get

    72k - (k-3) = 8 - (k-1)

    I am sure you can take it from there.

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