algebra
posted by Kim .
1/9 K+3/72k = 1/9k  k1/8k
i can't figure out how to get rid of the denominators

It is very important to use brackets.
I will assume you meant
1/9 (K+3)/(72k) = 1/(9k)  (k1)/(8k)
multiply each term by 72k to get
72k  (k3) = 8  (k1)
I am sure you can take it from there.
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