physics
posted by Elisa .
A quarterback throws a football toward a receiver with an initial speed of 21 m/s at an angle of 30° above the horizontal. At that instant, the receiver is 12 m from the quarterback. In what direction and with what constant speed should the receiver run in order to catch the football at the level at which it was thrown?

Using d = (V^2/g)sin2µ
the distance the football travels derives from d = (21^2/9.8)sin(60) = 38.97 m.
The time it will take the ball to reach the receivers hands derives from Vf = Vo  gt or 0 = 21sin60  9.8t making t = 1.85 sec.
Consequently, the receiver should run away from the quarterback at a speed of (38.97  12)/1.85 = 14.58m/s. 
that is the speed I originally got, but it is supposedly wrong.

Frig off
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