I have the equation 3f+2.50h=240 and I want to make a table of values with at least five possible combinations. How do I determine which combinations I should use?
You can pick any five you want.
How about h - -20, -15, 0, 15 and 20?
Solve for the f value in each case.
For example, if h = 0, f = 80
To determine which combinations of values to use in order to create a table of values, you need to select values for the variables "f" and "h" that satisfy the given equation. Let's break down the process step by step:
1. Start by selecting a value for one of the variables, let's say "f".
2. Substitute this value into the equation (3f + 2.50h = 240).
3. Solve the resulting equation for the other variable, "h".
4. Choose a value for "h" that satisfies the equation.
5. Write down the selected values for both "f" and "h" together as a combination.
6. Repeat the process by selecting different values for "f" to generate additional combinations.
7. Aim to have at least five different combinations to create a sufficient table of values.
Here's an example that demonstrates this process:
Let's assume we choose values for "f" from the set {10, 20, 30}.
For f = 10:
3(10) + 2.50h = 240
30 + 2.50h = 240
2.50h = 210
h = 84
Combination 1: f = 10, h = 84
For f = 20:
3(20) + 2.50h = 240
60 + 2.50h = 240
2.50h = 180
h = 72
Combination 2: f = 20, h = 72
For f = 30:
3(30) + 2.50h = 240
90 + 2.50h = 240
2.50h = 150
h = 60
Combination 3: f = 30, h = 60
By following this process, you can select different values of "f" and "h" and generate at least five different combinations to create a table of values.