2x^2-13x-7=0
If you use the box method, or just factor it. You should come up with (x-7)(2x+1)
To find the solutions to the given quadratic equation, 2x^2 - 13x - 7 = 0, you can use the quadratic formula. The quadratic formula states that for a quadratic equation ax^2 + bx + c = 0, the solution for x is given by:
x = (-b ± √(b^2 - 4ac)) / 2a
In this case, a = 2, b = -13, and c = -7. Plugging in these values into the quadratic formula, we get:
x = (-( -13) ± √((-13)^2 - 4(2)(-7))) / (2(2))
Simplifying further:
x = (13 ± √(169 + 56)) / 4
x = (13 ± √(225)) / 4
x = (13 ± 15) / 4
So, the two solutions to the quadratic equation are:
x = (13 + 15) / 4 = 28/4 = 7
and
x = (13 - 15) / 4 = -2/4 = -1/2
Therefore, the solutions to the equation 2x^2 - 13x - 7 = 0 are x = 7 and x = -1/2.