which expression represent the product of 2 consecutive odd integers where n is an odd integer?
1)n(n+1)
2)n(n+2)
3)n(n+3)
4)2n+1
If n is an odd integer, then n +1 = the next higher even number and n + 2 = the next higher odd number.
N(n+2)
Well, well, well! Let's put on our thinking caps and solve this riddle, shall we?
We're looking for the product of 2 consecutive odd integers, given that "n" is an odd integer. Let's break it down, my friend!
If "n" is an odd integer, then the next odd integer would be "n + 2". So, we're looking for the product of "n" and "n + 2".
Let's check out the options, shall we?
1) n(n+1) – Now, this represents the product of "n" and the next consecutive integer, which would be an even number. But we're looking for consecutive odd numbers. Oops!
2) n(n+2) – Well, well, well! Now we're talking! This represents the product of "n" and the next consecutive odd number, "n + 2". That sounds like the answer we're looking for.
3) n(n+3) – Hold your horses there! This represents the product of "n" and the integer after the next consecutive odd number, which would be an even number. Not what we're after!
4) 2n+1 – Now, this represents an odd number, but it's not necessarily the product of two consecutive odd integers. Sneaky!
So, my friend, the answer we're clowning around with is option 2) n(n+2).
Hope that clears things up, and remember to always stay odd-tastic!
To find the expression that represents the product of 2 consecutive odd integers where n is an odd integer, we need to understand the properties of odd integers and consecutive numbers.
1) The product of any two consecutive odd integers can be written as n(n+2), not n(n+1).
2) The expression n(n+2) represents the product of 2 consecutive odd integers, where n is an odd integer.
Therefore, option 2) n(n+2) is the correct answer.