Only a chemist can be trusted with the combination to the safe containing a ton of money. The combination is the pH of solution A, followed by the pH of solution C. (for example: is the pH of solution A is 3.47 and the pH of solution C is 8.15 the combination to the safe is 3-47-8-15) The chemist must determine the combination using only the information below (all solutions are at 25 degrees C)
Solution A is 50.00 mL of a 0.100 M solution of the weak monoprotic acid HX.
Solution B is a 0.0500 M solution of a salt NaX. It has a pH of 10.02.
Solution C is made by adding 15.00 mL of .250 M KOH to solution A.
What is the combination to the safe?
Based on how the yquestion said to state the answer i got 4-17-7-82
is that answer correct?
That looks good to me. I obtained 4-17-7-81 but the difference probably is rounding.
To find the combination to the safe, we need to determine the pH of solution A and the pH of solution C. Let's break down the given information step by step:
1. Solution A is 50.00 mL of a 0.100 M solution of the weak monoprotic acid HX.
- Since solution A contains a weak monoprotic acid, it can act as a buffer and help determine its pH.
- We need more information about the acid HX to calculate its pH. For now, let's keep this step on hold.
2. Solution B is a 0.0500 M solution of a salt NaX. It has a pH of 10.02.
- The pH of solution B is unrelated to the combination of the safe, so we can ignore it for now.
3. Solution C is made by adding 15.00 mL of 0.250 M KOH to solution A.
- KOH is a strong base, and when it reacts with the acid HX in solution A, it forms water and a salt.
- The salt formed will have a different pH compared to the original acid HX. Therefore, we need to calculate the new pH of solution C.
Now, to determine the pH for both solution A and C, we need some additional information about the acid HX. Please provide the acid dissociation constant (Ka) or any other relevant details about the weak monoprotic acid HX.