CAN SOMEONE PLEASE HELPPP!? I NEED HELP IN ALGEBRA, SIMPLIFYING RADICALS! SIMPLIFY THE SQUARE ROOT OF 45a SQUARED!
I believe the answer is 3a square root of 5a.
√)45a^2)
=√9 * √5 * √a^2
= 3a√5
answer is actually : 3a square root of 5.
45a^2 simplied is 9a^2 x 5
square root of 9a^2 is 3a.
Square root of 5 is radical 5.
Squaring your answer would check to see if you have the correct answer.
Thus mine is the correct one. Sarah was close.
thank you sarah reiny and chris !
oops, my bad. simple mistake.
Of course! I'd be happy to help you simplify the square root of 45a squared.
To simplify radicals, we want to simplify the numbers inside the square root and find any perfect squares that can be factored out.
Let's break down the given expression step by step:
1. Start with √(45a^2).
2. The first thing we can do is to look for perfect squares within the number 45. The perfect squares that are factors of 45 are 9 and 5, since 9 * 5 = 45.
3. Rewrite 45 as the product of its factors: 45 = 9 * 5.
4. The square root of 9 is 3, so we can simplify the square root of 45 to √(9 * 5).
5. Since the square root of 9 simplifies to 3, we can rewrite the expression as 3√(5a^2).
6. After that, we can further simplify by checking if there are any perfect squares within 5a^2. In this case, a^2 is already in its simplest form, so we leave it as it is.
7. The final simplified form is 3a√5.
To summarize, the square root of 45a squared simplifies to 3a√5.