calculus
posted by sarah .
let R be the region bounded by the graphs of y = sin(pie times x) and y = x^3  4.
a) find the area of R
b) the horizontal line y = 2 splits the region R into parts. write but do not evaluate an integral expression for the area of the part of R that is below this horizontal line.
c) The region R is the base of a solid. For this solid, each cross section perpendicular to xaxis is a square. Find the volume of this solid.
d) the region R models the surface of a small pond. At all points in R at a distance x from the yaxis, the depth of the water is given by h(x)=3x. find the volume of the water in the pound.

calculus 
Keifer
A. Area is the Integral of (sin(pi*X)(X^34X)) from 0 to 2 which should equal 4.
B. The horizontal line y=2 intersects the graph of X^34X at the points .539 and 1.675. The area is going to be the Integral of (sin(pi*X)(X^34X)) from .539 to 1.675
C. Volume= the integral of (sin(pi*X)(X^34X))^2 from 0 to 2 because the height is proportional to the width of the base. this should equal 9.978
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