im a little confuse on this problem.
"in the production of copper from ore containing copper(II) sulfide, the ore is first roasted to change it to the oxide according to the following equation: 2CuS + 2O2 --> 2CuO + 2CO2 [i already balanced it]
A. If 100 g of CuS and 56 g of O2 are available, which reactant is limiting?
B. Which reactant is in excess, and how many grams remain after the reaction is completed?
if you could tell me how you do it would be realllly helpful as well.
Thank you!
To determine which reactant is limiting and which is in excess, we need to compare the amounts of each reactant to the stoichiometry of the balanced equation.
A. Let's start by calculating the moles of each reactant:
- Moles of CuS = mass of CuS (100 g) / molar mass of CuS
- Moles of O2 = mass of O2 (56 g) / molar mass of O2
To find the molar masses of CuS and O2, we can refer to the periodic table. The molar mass of copper (Cu) is 63.55 g/mol, sulfur (S) is 32.07 g/mol, and oxygen (O) is 16.00 g/mol.
- Molar mass of CuS = molar mass of Cu (63.55 g/mol) + molar mass of S (32.07 g/mol)
- Molar mass of O2 = 2 x molar mass of O (16.00 g/mol)
Next, we calculate the moles:
- Moles of CuS = 100 g / (63.55 g/mol + 32.07 g/mol)
- Moles of O2 = 56 g / (2 x 16.00 g/mol)
Now we have the moles of each reactant.
B. To determine the limiting reactant, we need to compare the stoichiometric ratio in the balanced equation.
From the balanced equation: 2 moles of CuS react with 2 moles of O2 to produce 2 moles of CuO and 2 moles of CO2.
So, the ratio of CuS to O2 is 2:2, which simplifies to 1:1. This means that the reactants are present in the correct stoichiometric ratio.
Comparing the moles of CuS and O2 from Step A:
- Moles of CuS = calculated value
- Moles of O2 = calculated value
Since the moles of CuS and O2 are equal, neither reactant is limiting. This means that both reactants are in excess, and there will be no leftovers after the reaction is completed.
In summary:
A. Neither reactant is limiting.
B. Both reactants are in excess, and there are no leftovers after the reaction is completed.