# Math

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determine vertex, focus and directrix of parabola. then graph the parabola.

second equation:
y^2 -4y -12x= 8

Please help me this is do 2day bc i forget to turn it in to my teacher

• Math -

12 x + 8 = y^2 - 4 y
12 x + 12 = y^2 - 4 y + 4
so

(y-2)^2 = 12 (x+1) = 4*3 (x+1)

opens right

vertex at (-1,2)
focus to vertex = 3 so focus at (2,2)
directrix to vertex = 3 so directrix at x = -4

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