If y=x^2+2, fill in the following table for x = 0, 1, 2, 3, 4. Round to three decimal

For each x, use the formula y= x^2 + 2 to compute y. Then fill in the x,y pairs in your table.

When x=0, y=2
You should be able to do the others. For those integer value of x, y will also be an integer, and no "rounding of decimals" will be necessary.

To fill in the table for the equation y = x^2 + 2, we need to substitute the given values of x and calculate the corresponding values of y. Let's start by plugging in x = 0 into the equation:

y = (0)^2 + 2
y = 0 + 2
y = 2

So, when x = 0, y = 2. Next, let's substitute x = 1:

y = (1)^2 + 2
y = 1 + 2
y = 3

For x = 1, y = 3. Continuing with x = 2:

y = (2)^2 + 2
y = 4 + 2
y = 6

For x = 2, y = 6. Moving onto x = 3:

y = (3)^2 + 2
y = 9 + 2
y = 11

For x = 3, y = 11. Lastly, let's calculate for x = 4:

y = (4)^2 + 2
y = 16 + 2
y = 18

For x = 4, y = 18. Therefore, the filled-in table for x = 0, 1, 2, 3, 4 is as follows, rounded to three decimal places:

| x | y |
|-------|-------|
| 0 | 2 |
| 1 | 3 |
| 2 | 6 |
| 3 | 11 |
| 4 | 18 |