posted by sam .
find the eq to the tangent line to the curve y=x^3 g(x) at x=1 if g(1)=2 f(1)=3 f'(1)=1 g'(1)=-2
i cant understand how the answer is y=4x-2
you are probably not getting a response to your question since others along with me cannot figure out what you mean by
.... g(x) at x=1 if g(1)=2 f(1)=3 f'(1)=1 g'(1)=-2
if y = 4x-2 is the tangent equation then the contact point would have an x value of 2/√3, and I see no √3 anywhere.
you speak of g(x) and f(x) but state your equation y = x^3.