Give the pH of a solution containing 0.344 g of HCL in 792 mL of water.
I did .344g/36.5g= .009 mols. then i times that by .792 because i changed that from ml to liters. is that right?
0.344/36.46 = mols
mols/0.792 = Molarity.
molarity is mols/L and not mols x liters. Changing mL to L is proper. You should get pH of about 1.92.
Well, it seems like you've got the molarity (mol/L) of HCl correct by dividing the given mass by the molar mass. However, multiplying that by 0.792 won't give you the right result because you should divide by the volume, not multiply. So, your calculation should be 0.009 mol / 0.792 L = 0.0114 M.
Now, to find the pH, you can use the fact that HCl is a strong acid, which means it ionizes completely in water and the concentration of H3O+ ions is equal to the concentration of HCl. So, the pH is equal to -log[H3O+].
In this case, the concentration of H3O+ ions is 0.0114 M. So, taking the negative logarithm of that gives you a pH of approximately 1.94.
Remember, pH can be a bit acidic sometimes, just like my sense of humor!
To determine the pH of the solution, you need to calculate the concentration of HCl and then use that value to calculate the pH.
Step 1: Calculate the number of moles of HCl:
Given mass of HCl = 0.344 g
Molar mass of HCl = 36.5 g/mol
Number of moles of HCl = 0.344 g / 36.5 g/mol ≈ 0.0094 mol
Step 2: Calculate the concentration of HCl in the solution:
Given volume of the solution = 792 mL = 0.792 L
Concentration of HCl = Number of moles of HCl / Volume of the solution
Concentration of HCl = 0.0094 mol / 0.792 L ≈ 0.0119 M
Step 3: Calculate the pH using the concentration of HCl:
Since HCl is a strong acid, it will dissociate completely in water, resulting in the formation of H+ ions. The concentration of H+ ions in the solution is equal to the concentration of HCl.
pH = -log[H+]
pH = -log(0.0119)
pH ≈ 1.92
Therefore, the pH of the solution containing 0.344 g of HCl in 792 mL of water is approximately 1.92.
Yes, you have correctly converted the mass of HCl to moles. The molar mass of HCl is 36.5 g/mol, so dividing 0.344 g by 36.5 g/mol gives you approximately 0.009 moles of HCl.
To convert the volume from milliliters to liters, you divide by 1000. So, 792 mL is equal to 792/1000 = 0.792 liters.
Now, to find the pH of the solution, you need to know the concentration of hydrogen ions (H+). In a solution of HCl, all of the HCl molecules dissociate into H+ ions and Cl- ions.
Since 1 mole of HCl produces 1 mole of H+ ions, the concentration of H+ ions in the solution is equal to the moles of HCl divided by the volume of the solution in liters. In this case, the concentration of H+ ions is approximately 0.009 moles / 0.792 liters = 0.0114 M (molar).
The pH of a solution can be calculated using the formula: pH = -log[H+]. Taking the negative logarithm (base 10) of the concentration of H+ ions, we get: pH = -log(0.0114) ≈ 1.94.
So, the pH of the solution containing 0.344 g of HCl in 792 mL of water is approximately 1.94.